What is expand (ql^2(10-l))/(120) ?

The solution to expand (ql^2(10-l))/(120) is (l^2q)/(12)-(l^3q)/(120)

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expand (ql^2(10-l))/(120)

expand

\frac{q l ^{2} ( 10 - l )}{120}

\frac{l ^{2} q}{12} - \frac{l ^{3} q}{120}

Solution steps

\frac{q l ^{2} ( 10 - l )}{120}

Expand

q l^{2} (10 - l) : 10 l^{2} q - l^{3} q

= \frac{10 l ^{2} q - l ^{3} q}{120}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{10 l ^{2} q - l ^{3} q}{120} = \frac{10 l ^{2} q}{120} - \frac{l ^{3} q}{120}

= \frac{10 l ^{2} q}{120} - \frac{l ^{3} q}{120}

Cancel

\frac{10 l ^{2} q}{120} : \frac{l ^{2} q}{12}

= \frac{l ^{2} q}{12} - \frac{l ^{3} q}{120}

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What is expand (ql^2(10-l))/(120) ?
The solution to expand (ql^2(10-l))/(120) is (l^2q)/(12)-(l^3q)/(120)