What is expand ((x-3)^2x(x+3))/(10) ?

The solution to expand ((x-3)^2x(x+3))/(10) is (x^4)/(10)-(3x^3)/(10)-(9x^2)/(10)+(27x)/(10)

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expand ((x-3)^2x(x+3))/(10)

expand

\frac{( x - 3 ) ^{2} x ( x + 3 )}{10}

\frac{x ^{4}}{10} - \frac{3 x ^{3}}{10} - \frac{9 x ^{2}}{10} + \frac{27 x}{10}

Solution steps

\frac{( x - 3 ) ^{2} x ( x + 3 )}{10}

(x - 3)^{2} = x^{2} - 6 x + 9

= \frac{x ( x ^{2} - 6 x + 9 ) ( x + 3 )}{10}

Expand

(x^{2} - 6 x + 9) x (x + 3) : x^{4} - 3 x^{3} - 9 x^{2} + 27 x

= \frac{x ^{4} - 3 x ^{3} - 9 x ^{2} + 27 x}{10}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{4} - 3 x ^{3} - 9 x ^{2} + 27 x}{10} = \frac{x ^{4}}{10} - \frac{3 x ^{3}}{10} - \frac{9 x ^{2}}{10} + \frac{27 x}{10}

= \frac{x ^{4}}{10} - \frac{3 x ^{3}}{10} - \frac{9 x ^{2}}{10} + \frac{27 x}{10}

\frac{( x ^{2} - 2 x + 2 ) ln ( 6 x )}{x - 4}

\frac{1}{( x - 1 ) ( x - 6 ) ^{2}}

25 (\frac{p}{2} - 1)

\frac{4 ( 2 x - 3 )}{- 3 x + 1}

- \frac{1}{324} (6 - 2 z)^{4}

What is expand ((x-3)^2x(x+3))/(10) ?
The solution to expand ((x-3)^2x(x+3))/(10) is (x^4)/(10)-(3x^3)/(10)-(9x^2)/(10)+(27x)/(10)