What is expand (4(2x-3))/(-3x+1) ?

The solution to expand (4(2x-3))/(-3x+1) is (8x-12)/(-3x+1)

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expand (4(2x-3))/(-3x+1)

expand

\frac{4 ( 2 x - 3 )}{- 3 x + 1}

\frac{8 x - 12}{- 3 x + 1}

Solution steps

\frac{4 ( 2 x - 3 )}{- 3 x + 1}

Expand

4 (2 x - 3) : 8 x - 12

= \frac{8 x - 12}{- 3 x + 1}

- \frac{1}{324} (6 - 2 z)^{4}

(- a sin (t) - a sin (2 t))^{2} + (a cos (t) + a cos (2 t))^{2}

\frac{\partial}{\partial x} ((y) (3 x^{2} yz + 5 x z + 6))

f ((sin (x)) 2 x - 3)

164 (3 e^{4} + 4 e^{2} + 13)

What is expand (4(2x-3))/(-3x+1) ?
The solution to expand (4(2x-3))/(-3x+1) is (8x-12)/(-3x+1)