What is x(-(2xcos(x))/(x^2+1)-sin(x)) ?

The solution to x(-(2xcos(x))/(x^2+1)-sin(x)) is (x(-x^2sin(x)-sin(x)-2xcos(x)))/(x^2+1)

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simplify x(-(2xcos(x))/(x^2+1)-sin(x))

simplify

x (- \frac{2 x cos ( x )}{x ^{2} + 1} - sin (x))

\frac{x ( - x ^{2} sin ( x ) - sin ( x ) - 2 x cos ( x ) )}{x ^{2} + 1}

Solution steps

x (- \frac{2 x cos ( x )}{x ^{2} + 1} - sin (x))

Join

- \frac{2 x cos ( x )}{x ^{2} + 1} - sin (x) : \frac{- x ^{2} sin ( x ) - sin ( x ) - 2 x cos ( x )}{x ^{2} + 1}

= x \frac{- x ^{2} sin ( x ) - sin ( x ) - 2 x cos ( x )}{x ^{2} + 1}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{x ( - x ^{2} sin ( x ) - sin ( x ) - 2 x cos ( x ) )}{x ^{2} + 1}

x (3 x^{2} + 2 x + 1)

\frac{( x - 9 ) ( x + 4 )}{x}

(6 x - 8 y = 10,) - (- 15 x + 20 y = - 20)

\frac{30 j ^{2} + 51 j + 12}{20 j ( 3 j + 1 )}

e^{2 x} (- e^{- x} + C)

What is x(-(2xcos(x))/(x^2+1)-sin(x)) ?
The solution to x(-(2xcos(x))/(x^2+1)-sin(x)) is (x(-x^2sin(x)-sin(x)-2xcos(x)))/(x^2+1)