What is expand '(x-1)^4 ?

The solution to expand '(x-1)^4 is 'x^4-4'x^3+6'x^2-4'x+'

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expand '(x-1)^4

expand

^{'} (x - 1)^{4}

' x^{4} - 4' x^{3} + 6' x^{2} - 4' x +'

Solution steps

^{'} (x - 1)^{4}

(x - 1)^{4} = x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1

=^{^{'}} (x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1)

Distribute parentheses

=^{^{'}} x^{4} +^{^{'}} (- 4 x^{3}) +^{^{'}} 6 x^{2} +^{^{'}} (- 4 x) +^{^{'}} 1

Apply minus-plus rules

+ (- a) = - a

=^{^{'}} x^{4} - 4^{^{'}} x^{3} + 6^{^{'}} x^{2} - 4^{^{'}} x + 1^{^{'}}

Multiply:

1^{'} =^{'}

=^{^{'}} x^{4} - 4^{^{'}} x^{3} + 6^{^{'}} x^{2} - 4^{^{'}} x +^{^{'}}

\frac{x}{( x + 1 ) ( x - 2 )}

\frac{2 ( 6 - 6 )}{15}

x^{\frac{6}{7}} (x^{2} - 5)

2 c k x (\frac{b x - b d}{a} - 2 b + z)

2 (2 + 15)

What is expand '(x-1)^4 ?
The solution to expand '(x-1)^4 is 'x^4-4'x^3+6'x^2-4'x+'