What is (3+(9i)/n)^2 ?

The solution to (3+(9i)/n)^2 is (9n^2-81}{n^2}+\frac{54)/n i

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simplify (3+(9i)/n)^2

simplify

(3 + \frac{9 i}{n})^{2}

\frac{9 n ^{2} - 81}{n ^{2}} + \frac{54}{n} i

Solution steps

(3 + \frac{9 i}{n})^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(3 + \frac{9 i}{n})^{2} = 3^{2} + 2 \cdot 3 \cdot \frac{9 i}{n} + (\frac{9 i}{n})^{2}

= 3^{2} + 2 \cdot 3 \cdot \frac{9 i}{n} + (\frac{9 i}{n})^{2}

Simplify

3^{2} + 2 \cdot 3 \cdot \frac{9 i}{n} + (\frac{9 i}{n})^{2} : \frac{9 n ^{2} - 81}{n ^{2}} + \frac{54}{n} i

= \frac{9 n ^{2} - 81}{n ^{2}} + \frac{54}{n} i

\frac{6 - 5 s}{( s - 1 ) ( s ^{2} - 8 s + 17 )}

- e^{x} (e^{- x} + 1)^{3}

(tan (a) - 1) (sec (a) - 1)

(e^{x} sin (y) + 3 y) d x + (e^{x} sin (y) - 3 x) d y

\frac{2 ( x + 6 )}{3}

What is (3+(9i)/n)^2 ?
The solution to (3+(9i)/n)^2 is (9n^2-81}{n^2}+\frac{54)/n i