What is expand (d/(dt)(e(1-e^n)))/(1-e) ?

The solution to expand (d/(dt)(e(1-e^n)))/(1-e) is (d/(dt)(e-e^{1+n}))/(1-e)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (d/(dt)(e(1-e^n)))/(1-e)

expand

\frac{\frac{d}{d t} ( e ( 1 - e ^{n} ) )}{1 - e}

\frac{\frac{d}{d t} ( e - e ^{1 + n} )}{1 - e}

Solution steps

\frac{\frac{d}{d t} ( e ( 1 - e ^{n} ) )}{1 - e}

Expand

e (1 - e^{n}) : e - e^{1 + n}

= \frac{\frac{d}{d t} ( e - e ^{1 + n} )}{1 - e}

\frac{2 x ( 1 + x )}{( 1 + 2 x ) ^{2}}

(4 v^{2} - v sin (θ))^{2}

(4 x y + 2 x^{2} y) + (2 x^{2} + 3 y^{2}) y^{'} (x)

x^{3} \cdot e^{3 x^{2}} (2 x + 3)

x (x^{2} + \frac{x}{4} + 4)

What is expand (d/(dt)(e(1-e^n)))/(1-e) ?
The solution to expand (d/(dt)(e(1-e^n)))/(1-e) is (d/(dt)(e-e^{1+n}))/(1-e)