What is expand p^{1/5}(p^{4/5}+4p^{9/5}) ?

The solution to expand p^{1/5}(p^{4/5}+4p^{9/5}) is p+4p^2

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expand p^{1/5}(p^{4/5}+4p^{9/5})

expand

p^{\frac{1}{5}} (p^{\frac{4}{5}} + 4 p^{\frac{9}{5}})

p + 4 p^{2}

Solution steps

p^{\frac{1}{5}} (p^{\frac{4}{5}} + 4 p^{\frac{9}{5}})

Apply the distributive law:

a (b + c) = ab + a c

p^{\frac{1}{5}} (p^{\frac{4}{5}} + 4 p^{\frac{9}{5}}) = p^{\frac{1}{5}} p^{\frac{4}{5}} + p^{\frac{1}{5}} \cdot 4 p^{\frac{9}{5}}

= p^{\frac{1}{5}} p^{\frac{4}{5}} + p^{\frac{1}{5}} \cdot 4 p^{\frac{9}{5}}

p^{\frac{1}{5}} p^{\frac{4}{5}} = p

p^{\frac{1}{5}} \cdot 4 p^{\frac{9}{5}} = 4 p^{2}

= p + 4 p^{2}

(n + 1) (\frac{n ( 2 n + 1 )}{6} + 1)

\frac{10 ( 5 + 1985 )}{49}

(x^{2} - x) \cdot (x^{2} + x)

(2 x + 62 x)^{2}

\frac{d x}{( x + 3 a ) ( x + 4 a )}

What is expand p^{1/5}(p^{4/5}+4p^{9/5}) ?
The solution to expand p^{1/5}(p^{4/5}+4p^{9/5}) is p+4p^2