What is expand 1/((x^2-1)(x-1)) ?

The solution to expand 1/((x^2-1)(x-1)) is 1/(x^3-x^2-x+1)

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expand 1/((x^2-1)(x-1))

expand

\frac{1}{( x ^{2} - 1 ) ( x - 1 )}

\frac{1}{x ^{3} - x ^{2} - x + 1}

Solution steps

\frac{1}{( x ^{2} - 1 ) ( x - 1 )}

Expand

(x^{2} - 1) (x - 1) : x^{3} - x^{2} - x + 1

= \frac{1}{x ^{3} - x ^{2} - x + 1}

(x cos (a) + y cos (a + b) + z cos (a + b + c))^{2}

\frac{n ^{2} + 2}{n ^{2} ( n ^{2} + 4 )}

cos (t) h (t - \frac{π}{2})

\frac{3 ( 2 + 7 )}{3}

\frac{s + 1}{( s + 4 ) s ^{2}}

What is expand 1/((x^2-1)(x-1)) ?
The solution to expand 1/((x^2-1)(x-1)) is 1/(x^3-x^2-x+1)