What is (\partial)/(\partial t)((x)(x^2+y^2)) ?

The answer to (\partial)/(\partial t)((x)(x^2+y^2)) is 0

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(\partial)/(\partial t)((x)(x^2+y^2))

\frac{\partial}{\partial t} ((x) (x^{2} + y^{2}))

0

Solution steps

\frac{\partial}{\partial t} ((x) (x^{2} + y^{2}))

Treat

x, y

as constants

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\frac{K}{x ( 1 - x T )}

(x^{2} + 1) y^{'} (x) + x y - 2 x

(\frac{- 0.0433 - 0.0102 x}{0.0146})^{2}

(1 + \frac{1}{s}) (\frac{s}{s ^{2} + 1} + s + 1)

2 (ln (3) - 2 + \frac{2}{3})

What is (\partial)/(\partial t)((x)(x^2+y^2)) ?
The answer to (\partial)/(\partial t)((x)(x^2+y^2)) is 0