What is expand (2tu+u+t^2)de(-2t^2-4tu) ?

The solution to expand (2tu+u+t^2)de(-2t^2-4tu) is -2det^4-8det^3u-8det^2u^2-2det^2u-4detu^2

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expand (2tu+u+t^2)de(-2t^2-4tu)

expand

(2 t u + u + t^{2}) d e (- 2 t^{2} - 4 t u)

- 2 d e t^{4} - 8 d e t^{3} u - 8 d e t^{2} u^{2} - 2 d e t^{2} u - 4 d e t u^{2}

Solution steps

(2 t u + u + t^{2}) d e (- 2 t^{2} - 4 t u)

= d e (2 t u + u + t^{2}) (- 2 t^{2} - 4 t u)

Expand

(2 t u + u + t^{2}) (- 2 t^{2} - 4 t u) : - 2 t^{4} - 8 t^{3} u - 8 t^{2} u^{2} - 2 t^{2} u - 4 t u^{2}

= d e (- 2 t^{4} - 8 t^{3} u - 8 t^{2} u^{2} - 2 t^{2} u - 4 t u^{2})

Expand

d e (- 2 t^{4} - 8 t^{3} u - 8 t^{2} u^{2} - 2 t^{2} u - 4 t u^{2}) : - 2 d e t^{4} - 8 d e t^{3} u - 8 d e t^{2} u^{2} - 2 d e t^{2} u - 4 d e t u^{2}

= - 2 d e t^{4} - 8 d e t^{3} u - 8 d e t^{2} u^{2} - 2 d e t^{2} u - 4 d e t u^{2}

(x - 1)^{2} x - 1

((x^{3} + 3 x^{2} h + 3 x h^{2} + h^{3}) - 2) tan (x + h)

(4 x - 3) (x - 2 + i) (x + 2 - i)

20 + 2 (x - 3 = 8)

\frac{( t + 1 ) ^{2}}{3 ( 2 t ^{2} - 1 ) ^{3}}

What is expand (2tu+u+t^2)de(-2t^2-4tu) ?
The solution to expand (2tu+u+t^2)de(-2t^2-4tu) is -2det^4-8det^3u-8det^2u^2-2det^2u-4detu^2