What is expand (3x^2+4y^2=12)(1/12) ?

The solution to expand (3x^2+4y^2=12)(1/12) is (x^2)/4+(y^2)/3 =12

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expand (3x^2+4y^2=12)(1/12)

expand

(3 x^{2} + 4 y^{2} = 12) (\frac{1}{12})

\frac{x ^{2}}{4} + \frac{y ^{2}}{3} = 12

Solution steps

(3 x^{2} + 4 y^{2} = 12) (\frac{1}{12})

= (\frac{1}{12}) (3 x^{2} + 4 \cdot 12 = y^{2})

Apply the distributive law:

a (b + c) = ab + a c

a = (\frac{1}{12}), b = 3 x^{2}, c = 4 y^{2} = 12

(\frac{1}{12}) \cdot 3 x^{2} + (\frac{1}{12}) \cdot 4 y^{2} = 12

3 (\frac{1}{12}) x^{2} + 4 (\frac{1}{12}) y^{2} = 12

Expand

3 (\frac{1}{12}) x^{2} + 4 (\frac{1}{12}) y^{2} : \frac{x ^{2}}{4} + \frac{y ^{2}}{3}

\frac{x ^{2}}{4} + \frac{y ^{2}}{3} = 12

(T - b) \cdot (T - c) \cdot (T - d) \cdot (T - e) \cdot (T - f)

1 + 4 x^{2} (x^{2} - 1)

ln (3 uv w)

2 - 4 (1 - 3 x = 82)

(8, - 6) x (2, - 15)

What is expand (3x^2+4y^2=12)(1/12) ?
The solution to expand (3x^2+4y^2=12)(1/12) is (x^2)/4+(y^2)/3 =12