What is z^2(z/(z-3)-1-3/z) ?

The solution to z^2(z/(z-3)-1-3/z) is (9z)/(z-3)

Popular >

simplify z^2(z/(z-3)-1-3/z)

simplify

z^{2} (\frac{z}{z - 3} - 1 - \frac{3}{z})

\frac{9 z}{z - 3}

Solution steps

z^{2} (\frac{z}{z - 3} - 1 - \frac{3}{z})

Join

\frac{z}{z - 3} - 1 - \frac{3}{z} : \frac{9}{z ( z - 3 )}

= z^{2} \frac{9}{z ( z - 3 )}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{z ^{2} \cdot 9}{z ( z - 3 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

z^{2} = zz

= \frac{zz \cdot 9}{z ( z - 3 )}

Cancel the common factor:

z

= \frac{z \cdot 9}{z - 3}

= \frac{9 z}{z - 3}

(A x + B) (A x sin (x) + B x cos (x))

\frac{1 - x ^{2} cos ( x )}{( 1 + x sin ( x ) ) ^{2}}

f (x) = \frac{x ^{2} ( x + 1 ) ^{5}}{( x - 1 ) ^{4}}

\frac{s ^{2} - 2 s - 4}{6 ( s ^{3} - 3 s ^{2} - 3 s - 1 )}

x^{2} (1 - y^{2}) \frac{d y}{d x} + y^{2} (1 + x)