What is expand (e^xcos(e^x)-sin(e^x))*e^xcos(x) ?

The solution to expand (e^xcos(e^x)-sin(e^x))*e^xcos(x) is e^{2x}cos(x)cos(e^x)-e^xcos(x)sin(e^x)

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expand (e^xcos(e^x)-sin(e^x))*e^xcos(x)

expand

(e^{x} cos (e^{x}) - sin (e^{x})) \cdot e^{x} cos (x)

e^{2 x} cos (x) cos (e^{x}) - e^{x} cos (x) sin (e^{x})

Solution steps

(e^{x} cos (e^{x}) - sin (e^{x})) e^{x} cos (x)

= e^{x} cos (x) (e^{x} cos (e^{x}) - sin (e^{x}))

Apply the distributive law:

a (b - c) = ab - a c

a = e^{x} cos (x), b = e^{x} cos (e^{x}), c = sin (e^{x})

= e^{x} cos (x) e^{x} cos (e^{x}) - e^{x} cos (x) sin (e^{x})

= e^{x} e^{x} cos (x) cos (e^{x}) - e^{x} cos (x) sin (e^{x})

e^{x} e^{x} cos (x) cos (e^{x}) = e^{2 x} cos (x) cos (e^{x})

= e^{2 x} cos (x) cos (e^{x}) - e^{x} cos (x) sin (e^{x})

(3 x^{2} + y^{4}) \cdot 3 u v^{2} + 4 x y^{3} \cdot e^{w}

(4 \cdot 0.2) + (\frac{1}{5}) - (1 - 0.9) \cdot \frac{1}{2}

e^{t} cos (t) + (1 + e^{2 t})^{2} - 5 e^{- t} cosh (t)

(2 r sin (θ) - 1)^{2}

\frac{2 - 2 x}{2 y - 3 y ^{2} + 1} (1, - 1)

What is expand (e^xcos(e^x)-sin(e^x))*e^xcos(x) ?
The solution to expand (e^xcos(e^x)-sin(e^x))*e^xcos(x) is e^{2x}cos(x)cos(e^x)-e^xcos(x)sin(e^x)