What is (sqrt(x+1)+2)(sqrt(x+1)-2)(x^2+7) ?

The solution to (sqrt(x+1)+2)(sqrt(x+1)-2)(x^2+7) is (x-3)(x^2+7)

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simplify (sqrt(x+1)+2)(sqrt(x+1)-2)(x^2+7)

simplify

(x + 1 + 2) (x + 1 - 2) (x^{2} + 7)

(x - 3) (x^{2} + 7)

Solution steps

(x + 1 + 2) (x + 1 - 2) (x^{2} + 7)

Apply Difference of Two Squares Formula:

(a + b) (a - b) = a^{2} - b^{2}

(x + 1 + 2) (x + 1 - 2) = (x + 1)^{2} - 2^{2}

= ((x + 1)^{2} - 2^{2}) (x^{2} + 7)

Simplify

(x + 1)^{2} - 2^{2} : x - 3

= (x - 3) (x^{2} + 7)

(x + 2)^{2 (x - 1)}

\frac{3 s ^{2} + 2 s + 1}{( s ^{2} + 1 ) ( s ^{2} + 2 s + 2 )}

(b cos (z) - a sin (z) y) \cdot 2 r sin (z)

\frac{3}{e ( \frac{a}{x} - 2 ) - 1}

\frac{3 s - 14}{( s - 2 ) ( s - 5 )}

What is (sqrt(x+1)+2)(sqrt(x+1)-2)(x^2+7) ?
The solution to (sqrt(x+1)+2)(sqrt(x+1)-2)(x^2+7) is (x-3)(x^2+7)