What is expand (8pi(2-sqrt(2)))/3 ?

The solution to expand (8pi(2-sqrt(2)))/3 is (16pi)/3-(8sqrt(2)pi)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (8pi(2-sqrt(2)))/3

expand

\frac{8 π ( 2 - 2 )}{3}

\frac{16 π}{3} - \frac{8 2 π}{3}

Decimal Notation

4.90747 \dots

Solution steps

\frac{8 π ( 2 - 2 )}{3}

Expand

8 π (2 - 2) : 16 π - 82 π

= \frac{16 π - 8 2 π}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{16 π - 8 2 π}{3} = \frac{16 π}{3} - \frac{8 2 π}{3}

= \frac{16 π}{3} - \frac{8 2 π}{3}

\frac{e}{3 ( n + 1 ) ( 3 n + 2 ) ( 3 n + 1 )}

(x - 2 + i)^{2}

(1250 - x) + (- \frac{5100}{( 0.02 x + 1 ) ^{2}})

\frac{- x ^{2} + 12 x - 35}{( x ^{2} - 6 x + 1 ) ^{2}}

(2 x - 4) (2 x^{2} - 8 x + 35)^{4} d x

What is expand (8pi(2-sqrt(2)))/3 ?
The solution to expand (8pi(2-sqrt(2)))/3 is (16pi)/3-(8sqrt(2)pi)/3