What is expand-2(-2e^{-2x}x^2+2e^{-2x}x) ?

The solution to expand-2(-2e^{-2x}x^2+2e^{-2x}x) is 4e^{-2x}x^2-4e^{-2x}x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-2(-2e^{-2x}x^2+2e^{-2x}x)

expand

- 2 (- 2 e^{- 2 x} x^{2} + 2 e^{- 2 x} x)

4 e^{- 2 x} x^{2} - 4 e^{- 2 x} x

Solution steps

- 2 (- 2 e^{- 2 x} x^{2} + 2 e^{- 2 x} x)

Apply the distributive law:

a (b + c) = ab + a c

a = - 2, b = - 2 e^{- 2 x} x^{2}, c = 2 e^{- 2 x} x

= - 2 (- 2 e^{- 2 x} x^{2}) + (- 2) \cdot 2 e^{- 2 x} x

Apply minus-plus rules

- (- a) = a, + (- a) = - a

= 2 \cdot 2 e^{- 2 x} x^{2} - 2 \cdot 2 e^{- 2 x} x

Multiply the numbers:

2 \cdot 2 = 4

= 4 e^{- 2 x} x^{2} - 4 e^{- 2 x} x

(2 x + cos (x)) (3 - e^{x})

\frac{( 4 e ^{x} ( 4 - e ^{x} ) )}{( 4 + e ^{x} ) ^{3}}

(\frac{1}{t} - i)^{2}

ln (x^{2} + 1) + (sin (x) + 5)^{4}

\frac{8 ( 6 6 - 5 5 )}{3} - 9

What is expand-2(-2e^{-2x}x^2+2e^{-2x}x) ?
The solution to expand-2(-2e^{-2x}x^2+2e^{-2x}x) is 4e^{-2x}x^2-4e^{-2x}x