What is expand ((2-x)(x-3)(x-4)*7)/(24) ?

The solution to expand ((2-x)(x-3)(x-4)*7)/(24) is -(7x^3}{24}+(21x^2)/8-\frac{91x)/(12)+7

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expand ((2-x)(x-3)(x-4)*7)/(24)

expand

\frac{( 2 - x ) ( x - 3 ) ( x - 4 ) \cdot 7}{24}

- \frac{7 x ^{3}}{24} + \frac{21 x ^{2}}{8} - \frac{91 x}{12} + 7

Solution steps

\frac{( 2 - x ) ( x - 3 ) ( x - 4 ) \cdot 7}{24}

Expand

(2 - x) (x - 3) (x - 4) \cdot 7 : - 7 x^{3} + 63 x^{2} - 182 x + 168

= \frac{- 7 x ^{3} + 63 x ^{2} - 182 x + 168}{24}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 7 x ^{3} + 63 x ^{2} - 182 x + 168}{24} = - \frac{7 x ^{3}}{24} + \frac{63 x ^{2}}{24} - \frac{182 x}{24} + \frac{168}{24}

= - \frac{7 x ^{3}}{24} + \frac{63 x ^{2}}{24} - \frac{182 x}{24} + \frac{168}{24}

Cancel

\frac{63 x ^{2}}{24} : \frac{21 x ^{2}}{8}

= - \frac{7 x ^{3}}{24} + \frac{21 x ^{2}}{8} - \frac{182 x}{24} + \frac{168}{24}

Cancel

\frac{182 x}{24} : \frac{91 x}{12}

= - \frac{7 x ^{3}}{24} + \frac{21 x ^{2}}{8} - \frac{91 x}{12} + \frac{168}{24}

Divide the numbers:

\frac{168}{24} = 7

= - \frac{7 x ^{3}}{24} + \frac{21 x ^{2}}{8} - \frac{91 x}{12} + 7

x (3 x - 5)

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(2 x + 1) \cdot ln (2 x + 1)

- sin (x) \cdot (6 (2 x + 1)^{2})

(4 x^{2} - 5 y^{2} + x) d x + x y d y

What is expand ((2-x)(x-3)(x-4)*7)/(24) ?
The solution to expand ((2-x)(x-3)(x-4)*7)/(24) is -(7x^3}{24}+(21x^2)/8-\frac{91x)/(12)+7