What is expand e^{1+t}u(-t+2) ?

The solution to expand e^{1+t}u(-t+2) is -e^{1+t}tu+2e^{1+t}u

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expand e^{1+t}u(-t+2)

expand

e^{1 + t} u (- t + 2)

- e^{1 + t} t u + 2 e^{1 + t} u

Solution steps

e^{1 + t} u (- t + 2)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{1 + t} u, b = - t, c = 2

= e^{1 + t} u (- t) + e^{1 + t} u \cdot 2

Apply minus-plus rules

+ (- a) = - a

= - e^{1 + t} t u + 2 e^{1 + t} u

\frac{2 x ^{2} - 2 x - 4}{( 2 x - 1 ) ^{2}}

\frac{3}{4} (x + \frac{1}{2} sin (2 x))

f or (x^{4} + 20 - \frac{x ^{4}}{12})

\frac{918 x ^{2} - 21 x - 124}{2 ( 6 x ^{2} - 5 x + 4 ) ( 9 x + 4 )}

What is expand e^{1+t}u(-t+2) ?
The solution to expand e^{1+t}u(-t+2) is -e^{1+t}tu+2e^{1+t}u