What is expand (9x+12)/((2x+3)(x-5)) ?

The solution to expand (9x+12)/((2x+3)(x-5)) is (9x+12)/(2x^2-7x-15)

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expand (9x+12)/((2x+3)(x-5))

expand

\frac{9 x + 12}{( 2 x + 3 ) ( x - 5 )}

\frac{9 x + 12}{2 x ^{2} - 7 x - 15}

Solution steps

\frac{9 x + 12}{( 2 x + 3 ) ( x - 5 )}

Expand

(2 x + 3) (x - 5) : 2 x^{2} - 7 x - 15

= \frac{9 x + 12}{2 x ^{2} - 7 x - 15}

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What is expand (9x+12)/((2x+3)(x-5)) ?
The solution to expand (9x+12)/((2x+3)(x-5)) is (9x+12)/(2x^2-7x-15)