What is expand ((x-4)(x-7))/(2x^2(x-8)) ?

The solution to expand ((x-4)(x-7))/(2x^2(x-8)) is (x^2-11x+28)/(2x^3-16x^2)

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expand ((x-4)(x-7))/(2x^2(x-8))

expand

\frac{( x - 4 ) ( x - 7 )}{2 x ^{2} ( x - 8 )}

\frac{x ^{2} - 11 x + 28}{2 x ^{3} - 16 x ^{2}}

Solution steps

\frac{( x - 4 ) ( x - 7 )}{2 x ^{2} ( x - 8 )}

Expand

2 x^{2} (x - 8) : 2 x^{3} - 16 x^{2}

= \frac{( x - 4 ) ( x - 7 )}{2 x ^{3} - 16 x ^{2}}

Expand

(x - 4) (x - 7) : x^{2} - 11 x + 28

= \frac{x ^{2} - 11 x + 28}{2 x ^{3} - 16 x ^{2}}

\frac{2 ( 2 v ^{3} - 11 v ^{2} + 22 v - 15 )}{2 x - 3}

\frac{( s + 1 )}{( ( s ^{2} - 4 s ) ( s + 5 ) )}

\frac{10 ( 1 + 61 )}{7}

- 400 (3993 - 802)

(6 - π)^{2}

What is expand ((x-4)(x-7))/(2x^2(x-8)) ?
The solution to expand ((x-4)(x-7))/(2x^2(x-8)) is (x^2-11x+28)/(2x^3-16x^2)