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Popular >

d/(dt)((s)(3t^2-sec(t)+3))

Solution

\frac{d}{d t} ((s) (3 t^{2} - sec (t) + 3))

Solution

s (6 t - sec (t) tan (t))

Solution steps

\frac{d}{d t} ((s) (3 t^{2} - sec (t) + 3))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= s \frac{d}{d t} (3 t^{2} - sec (t) + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= s (\frac{d}{d t} (3 t^{2}) - \frac{d}{d t} (sec (t)) + \frac{d}{d t} (3))

\frac{d}{d t} (3 t^{2}) = 6 t

\frac{d}{d t} (sec (t)) = sec (t) tan (t)

\frac{d}{d t} (3) = 0

= s (6 t - sec (t) tan (t) + 0)

Simplify

= s (6 t - sec (t) tan (t))

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Frequently Asked Questions (FAQ)

What is the d/(dt)((s)(3t^2-sec(t)+3)) ?
The d/(dt)((s)(3t^2-sec(t)+3)) is s(6t-sec(t)tan(t))
What is the first d/(dt)((s)(3t^2-sec(t)+3)) ?
The first d/(dt)((s)(3t^2-sec(t)+3)) is s(6t-sec(t)tan(t))