What is expand x^2y''(x)+xy'(x)+(x^2-4)y ?

The solution to expand x^2y''(x)+xy'(x)+(x^2-4)y is x^2y''(x)+xy'(x)+x^2y-4y

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expand x^2y''(x)+xy'(x)+(x^2-4)y

expand

x^{2} y^{''} (x) + x y^{'} (x) + (x^{2} - 4) y

x^{2} y'' (x) + x y' (x) + x^{2} y - 4 y

Solution steps

x^{2} y^{''} (x) + x y^{'} (x) + (x^{2} - 4) y

Expand

y (x^{2} - 4) : x^{2} y - 4 y

= x^{2} y^{''} (x) + x y^{'} (x) + x^{2} y - 4 y

\frac{n ^{2} ( 4 ^{n} )}{( n + 1 ) ( n + 2 )}

- 4 (= 2 p + 10)

\frac{1}{s ^{2} ( s ^{2} - a )}

(1 - \frac{1}{( x + 28 ) ^{2}}) (1 - \frac{1}{( x + 29 ) ^{2}})

What is expand x^2y''(x)+xy'(x)+(x^2-4)y ?
The solution to expand x^2y''(x)+xy'(x)+(x^2-4)y is x^2y''(x)+xy'(x)+x^2y-4y