What is 3(((-1)^{k-1})/2+1) ?

The solution to 3(((-1)^{k-1})/2+1) is (3(2+(-1)^{k-1}))/2

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simplify 3(((-1)^{k-1})/2+1)

simplify

3 (\frac{( - 1 ) ^{k - 1}}{2} + 1)

\frac{3 ( 2 + ( - 1 ) ^{k - 1} )}{2}

Solution steps

3 (\frac{( - 1 ) ^{k - 1}}{2} + 1)

Join

\frac{( - 1 ) ^{k - 1}}{2} + 1 : \frac{2 + ( - 1 ) ^{k - 1}}{2}

= 3 \cdot \frac{2 + ( - 1 ) ^{k - 1}}{2}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 ( 2 + ( - 1 ) ^{k - 1} )}{2}

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What is 3(((-1)^{k-1})/2+1) ?
The solution to 3(((-1)^{k-1})/2+1) is (3(2+(-1)^{k-1}))/2