What is expand (3x+3dx-5)(3x+3dx-5) ?

The solution to expand (3x+3dx-5)(3x+3dx-5) is 9x^2+18xdx-30x+9dx^2-30dx+25

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expand (3x+3dx-5)(3x+3dx-5)

expand

(3 x + 3 d x - 5) (3 x + 3 d x - 5)

9 x^{2} + 18 x d x - 30 x + 9 d x^{2} - 30 d x + 25

Solution steps

(3 x + 3 d x - 5) (3 x + 3 d x - 5)

Distribute parentheses

= 3 x \cdot 3 x + 3 x \cdot 3 d x + 3 x (- 5) + 3 d x \cdot 3 x + 3 d x \cdot 3 d x + 3 d x (- 5) + (- 5) \cdot 3 x + (- 5) \cdot 3 d x + (- 5) (- 5)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= 3 \cdot 3 xx + 3 \cdot 3 x d x - 3 \cdot 5 x + 3 \cdot 3 x d x + 3 \cdot 3 d x d x - 3 \cdot 5 d x - 5 \cdot 3 x - 5 \cdot 3 d x + 5 \cdot 5

Simplify

3 \cdot 3 xx + 3 \cdot 3 x d x - 3 \cdot 5 x + 3 \cdot 3 x d x + 3 \cdot 3 d x d x - 3 \cdot 5 d x - 5 \cdot 3 x - 5 \cdot 3 d x + 5 \cdot 5 : 9 x^{2} + 18 x d x - 30 x + 9 d x^{2} - 30 d x + 25

= 9 x^{2} + 18 x d x - 30 x + 9 d x^{2} - 30 d x + 25

x^{2} \cdot (ln (x + 2) - 1) d x

- \frac{3}{4} (x + 2) (x + 1) (x - 3)

\frac{20 ( 5 + 2 5 )}{3}

\frac{200 - 200 ( 1 - x ) ^{\frac{1}{3}}}{( 1 - x ) ^{\frac{1}{3}}}

(\frac{2 i}{n} + 1)^{2}

What is expand (3x+3dx-5)(3x+3dx-5) ?
The solution to expand (3x+3dx-5)(3x+3dx-5) is 9x^2+18xdx-30x+9dx^2-30dx+25