What is expand-log_{10}(2)(6-x) ?

The solution to expand-log_{10}(2)(6-x) is -6log_{10}(2)+log_{10}(2)x

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expand-log_{10}(2)(6-x)

expand

- lo g_{10} (2) (6 - x)

- 6 lo g_{10} (2) + lo g_{10} (2) x

Solution steps

- lo g_{10} (2) (6 - x)

Apply the distributive law:

a (b - c) = ab - a c

- lo g_{10} (2) (6 - x) = - lo g_{10} (2) \cdot 6 - (- lo g_{10} (2)) x

= - lo g_{10} (2) \cdot 6 - (- lo g_{10} (2)) x

Simplify

- lo g_{10} (2) \cdot 6 - (- lo g_{10} (2)) x : - 6 lo g_{10} (2) + lo g_{10} (2) x

= - 6 lo g_{10} (2) + lo g_{10} (2) x

\frac{8 s ^{2} + 18}{( s ^{2} + 4 s + 6 ) ^{2}}

(- sin (t) + cos (t)) (- cos (t) - sin (t))

F (R (t)) y F (1, - 1, 1)

(3 + j^{3}) \cdot (1 + j 3)

(x^{2} + 2) cos (3 x + 4)

What is expand-log_{10}(2)(6-x) ?
The solution to expand-log_{10}(2)(6-x) is -6log_{10}(2)+log_{10}(2)x