What is (x-4)(x+1)(x+1/2)(x-4/3) ?

The solution to (x-4)(x+1)(x+1/2)(x-4/3) is ((x-4)(x+1)(2x+1)(3x-4))/6

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simplify (x-4)(x+1)(x+1/2)(x-4/3)

simplify

(x - 4) (x + 1) (x + \frac{1}{2}) (x - \frac{4}{3})

\frac{( x - 4 ) ( x + 1 ) ( 2 x + 1 ) ( 3 x - 4 )}{6}

Solution steps

(x - 4) (x + 1) (x + \frac{1}{2}) (x - \frac{4}{3})

Simplify

x + \frac{1}{2} : \frac{2 x + 1}{2}

= (x - 4) (x + 1) \frac{2 x + 1}{2} (x - \frac{4}{3})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x - 4 ) ( x + 1 ) ( 2 x + 1 ) ( x - \frac{4}{3} )}{2}

Simplify

(x - 4) (x + 1) (2 x + 1) (x - \frac{4}{3}) : \frac{( x - 4 ) ( x + 1 ) ( 2 x + 1 ) ( x \cdot 3 - 4 )}{3}

= \frac{\frac{( x - 4 ) ( x + 1 ) ( 2 x + 1 ) ( x \cdot 3 - 4 )}{3}}{2}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( x - 4 ) ( x + 1 ) ( 2 x + 1 ) ( x \cdot 3 - 4 )}{3 \cdot 2}

Multiply the numbers:

3 \cdot 2 = 6

= \frac{( x - 4 ) ( x + 1 ) ( 2 x + 1 ) ( x \cdot 3 - 4 )}{6}

= \frac{( x - 4 ) ( x + 1 ) ( 2 x + 1 ) ( 3 x - 4 )}{6}

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What is (x-4)(x+1)(x+1/2)(x-4/3) ?
The solution to (x-4)(x+1)(x+1/2)(x-4/3) is ((x-4)(x+1)(2x+1)(3x-4))/6