What is expand 7(3x+1)+8(2x-3=4)(3x-1)-7(x-4) ?

The solution to expand 7(3x+1)+8(2x-3=4)(3x-1)-7(x-4) is 48x^2+5x-17=-7x+32

Popular >

expand 7(3x+1)+8(2x-3=4)(3x-1)-7(x-4)

expand

7 (3 x + 1) + 8 (2 x - 3 = 4) (3 x - 1) - 7 (x - 4)

48 x^{2} + 5 x - 17 = - 7 x + 32

Solution steps

7 (3 x + 1) + 8 (2 x - 3 = 4) (3 x - 1) - 7 (x - 4)

= 7 (3 x + 1) + 8 (2 x - 3 \cdot 4 =) (3 x - 1) - 7 (x - 4)

Expand

7 (3 x + 1) : 21 x + 7

= 21 x + 7 + 8 (2 x - 3 = 4) (3 x - 1) - 7 (x - 4)

Expand

8 (2 x - 3 = 4) (3 x - 1) : 48 x^{2} - 16 x - 24 = 4

21 x + 7 + 48 x^{2} - 16 x - 24 = 4 - 7 (x - 4)

Expand

- 7 (x - 4) : - 7 x + 28

21 x + 7 + 48 x^{2} - 16 x - 24 = 4 - 7 x + 28

Simplify

21 x + 7 + 48 x^{2} - 16 x - 24 = 4 - 7 x + 28 : 48 x^{2} + 5 x - 17 = - 7 x + 32

48 x^{2} + 5 x - 17 = - 7 x + 32

7 l e f (t, a) t (a + 5) - 3 0^{^{'}}

\frac{x ^{6} ( x - 6 ) ^{6}}{( x ^{2} + 8 ) ^{6}}

\frac{160 x ^{6} + 50000 x ^{3}}{3 ( 2 x + 5 ) ^{5}}

\frac{( k + 2 ) ( 2 k + 3 ) ( 2 k + 5 )}{3}

What is expand 7(3x+1)+8(2x-3=4)(3x-1)-7(x-4) ?
The solution to expand 7(3x+1)+8(2x-3=4)(3x-1)-7(x-4) is 48x^2+5x-17=-7x+32