What is expand ((e^{-2t})(cos(t)-cos(2t)))/t ?

The solution to expand ((e^{-2t})(cos(t)-cos(2t)))/t is (e^{-2t}cos(t))/t-(e^{-2t}cos(2t))/t

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expand ((e^{-2t})(cos(t)-cos(2t)))/t

expand

\frac{( e ^{- 2 t} ) ( cos ( t ) - cos ( 2 t ) )}{t}

\frac{e ^{- 2 t} cos ( t )}{t} - \frac{e ^{- 2 t} cos ( 2 t )}{t}

Solution steps

\frac{( e ^{- 2 t} ) ( cos ( t ) - cos ( 2 t ) )}{t}

Remove parentheses:

(a) = a

= \frac{e ^{- 2 t} ( cos ( t ) - cos ( 2 t ) )}{t}

Expand

e^{- 2 t} (cos (t) - cos (2 t)) : e^{- 2 t} cos (t) - e^{- 2 t} cos (2 t)

= \frac{e ^{- 2 t} cos ( t ) - e ^{- 2 t} cos ( 2 t )}{t}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{e ^{- 2 t} cos ( t ) - e ^{- 2 t} cos ( 2 t )}{t} = \frac{e ^{- 2 t} cos ( t )}{t} - \frac{e ^{- 2 t} cos ( 2 t )}{t}

= \frac{e ^{- 2 t} cos ( t )}{t} - \frac{e ^{- 2 t} cos ( 2 t )}{t}

d x (9 x^{2} + 7)

- \frac{2 x + h}{( x ^{2} - 4 ) ( ( x + h ) ^{2} - 4 )}

- 5 (x + Δ x)^{4}

(- 5, 1 - 65) (- 5, 8) y (- 5, - 6)

A (- \frac{1}{2}, 3) y B (4, - \frac{2}{3})

What is expand ((e^{-2t})(cos(t)-cos(2t)))/t ?
The solution to expand ((e^{-2t})(cos(t)-cos(2t)))/t is (e^{-2t}cos(t))/t-(e^{-2t}cos(2t))/t