What is expand (3s-33)/((s^2+9)(s+2)(s-1)) ?

The solution to expand (3s-33)/((s^2+9)(s+2)(s-1)) is (3s-33)/(s^4+s^3+7s^2+9s-18)

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expand (3s-33)/((s^2+9)(s+2)(s-1))

expand

\frac{3 s - 33}{( s ^{2} + 9 ) ( s + 2 ) ( s - 1 )}

\frac{3 s - 33}{s ^{4} + s ^{3} + 7 s ^{2} + 9 s - 18}

Solution steps

\frac{3 s - 33}{( s ^{2} + 9 ) ( s + 2 ) ( s - 1 )}

Expand

(s^{2} + 9) (s + 2) (s - 1) : s^{4} + s^{3} + 7 s^{2} + 9 s - 18

= \frac{3 s - 33}{s ^{4} + s ^{3} + 7 s ^{2} + 9 s - 18}

2 (x^{3} - \frac{1}{x ^{3}})

sin (2) (x + h)

sin (3) (x^{2} + 1)

3000 cos (0.5 (x - 1)) + 10000

(\frac{( 2 x + 8 )}{6})^{3}

What is expand (3s-33)/((s^2+9)(s+2)(s-1)) ?
The solution to expand (3s-33)/((s^2+9)(s+2)(s-1)) is (3s-33)/(s^4+s^3+7s^2+9s-18)