What is expand (-1+e^{-x/(Bw)})(e^{-1/A}-1) ?

The solution to expand (-1+e^{-x/(Bw)})(e^{-1/A}-1) is -e^{-1/A}+1+e^{-x/(Bw)-1/A}-e^{-x/(Bw)}

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expand (-1+e^{-x/(Bw)})(e^{-1/A}-1)

expand

(- 1 + e^{- \frac{x}{Bw}}) (e^{- \frac{1}{A}} - 1)

- e^{- \frac{1}{A}} + 1 + e^{- \frac{x}{Bw} - \frac{1}{A}} - e^{- \frac{x}{Bw}}

Solution steps

(- 1 + e^{- \frac{x}{Bw}}) (e^{- \frac{1}{A}} - 1)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = - 1, b = e^{- \frac{x}{Bw}}, c = e^{- \frac{1}{A}}, d = - 1

= (- 1) e^{- \frac{1}{A}} + (- 1) (- 1) + e^{- \frac{x}{Bw}} e^{- \frac{1}{A}} + e^{- \frac{x}{Bw}} (- 1)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= - 1 \cdot e^{- \frac{1}{A}} + 1 \cdot 1 + e^{- \frac{x}{Bw}} e^{- \frac{1}{A}} - 1 \cdot e^{- \frac{x}{Bw}}

Simplify

- 1 \cdot e^{- \frac{1}{A}} + 1 \cdot 1 + e^{- \frac{x}{Bw}} e^{- \frac{1}{A}} - 1 \cdot e^{- \frac{x}{Bw}} : - e^{- \frac{1}{A}} + 1 + e^{- \frac{x}{Bw} - \frac{1}{A}} - e^{- \frac{x}{Bw}}

= - e^{- \frac{1}{A}} + 1 + e^{- \frac{x}{Bw} - \frac{1}{A}} - e^{- \frac{x}{Bw}}

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What is expand (-1+e^{-x/(Bw)})(e^{-1/A}-1) ?
The solution to expand (-1+e^{-x/(Bw)})(e^{-1/A}-1) is -e^{-1/A}+1+e^{-x/(Bw)-1/A}-e^{-x/(Bw)}