What is expand (e^{7x}+e^{-7x})(e^{7x}-e^{-7x}) ?

The solution to expand (e^{7x}+e^{-7x})(e^{7x}-e^{-7x}) is e^{14x}-e^{-14x}

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expand (e^{7x}+e^{-7x})(e^{7x}-e^{-7x})

expand

(e^{7 x} + e^{- 7 x}) (e^{7 x} - e^{- 7 x})

e^{14 x} - e^{- 14 x}

Solution steps

(e^{7 x} + e^{- 7 x}) (e^{7 x} - e^{- 7 x})

Apply Difference of Two Squares Formula:

(a + b) (a - b) = a^{2} - b^{2}

a = e^{7 x}, b = e^{- 7 x}

= (e^{7 x})^{2} - (e^{- 7 x})^{2}

Simplify

(e^{7 x})^{2} - (e^{- 7 x})^{2} : e^{14 x} - e^{- 14 x}

= e^{14 x} - e^{- 14 x}

f (n) = (1 1^{n + 1} - 4^{n + 1}) mod 7

\frac{2 x ^{3} + x ^{2} + 8 x + 6}{( x ^{2} + 4 ) ( x ^{2} + 1 )}

\frac{6 ( k + 126 ) ( - k ^{2} + 1001 k - 132930 )}{k - 4238}

x (2 lo g_{10} (x) + 1)

- 4 (m + 6 = - 8)

What is expand (e^{7x}+e^{-7x})(e^{7x}-e^{-7x}) ?
The solution to expand (e^{7x}+e^{-7x})(e^{7x}-e^{-7x}) is e^{14x}-e^{-14x}