What is (\partial)/(\partial u)((y)(u+v)) ?

The answer to (\partial)/(\partial u)((y)(u+v)) is y

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(\partial)/(\partial u)((y)(u+v))

\frac{\partial}{\partial u} ((y) (u + v))

y

Solution steps

\frac{\partial}{\partial u} ((y) (u + v))

Treat

y, v

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial u} (u + v)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= y (\frac{\partial}{\partial u} (u) + \frac{\partial}{\partial u} (v))

\frac{\partial}{\partial u} (u) = 1

\frac{\partial}{\partial u} (v) = 0

= y (1 + 0)

Simplify

= y

\frac{( 0.04 - x ) ( x )}{0.12 - x}

\frac{d}{d y} ((x) (x^{2} + 2 x + 1))

(x^{2} + \frac{1}{2 x})^{11}

\frac{1 - 2 ( a + h ) ^{2} - 1 - 2 a ^{2}}{h}

(f \circ g) (\frac{f}{- x ^{2}} + 1) (\frac{g}{- x} + 1)

What is (\partial)/(\partial u)((y)(u+v)) ?
The answer to (\partial)/(\partial u)((y)(u+v)) is y