What is (f\circ g)(f/(-x^2)+1)(g/(-x)+1) ?

The solution to (f\circ g)(f/(-x^2)+1)(g/(-x)+1) is \circ fg(-f/(x^2)+1)(-g/x+1)

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simplify (f\circ g)(f/(-x^2)+1)(g/(-x)+1)

simplify

(f \circ g) (\frac{f}{- x ^{2}} + 1) (\frac{g}{- x} + 1)

\circ f g (- \frac{f}{x ^{2}} + 1) (- \frac{g}{x} + 1)

Solution steps

(f \circ g) (\frac{f}{- x ^{2}} + 1) (\frac{g}{- x} + 1)

Remove parentheses:

(a) = a

= f \circ g (\frac{f}{- x ^{2}} + 1) (\frac{g}{- x} + 1)

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= \circ f g (- \frac{f}{x ^{2}} + 1) (\frac{g}{- x} + 1)

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= \circ f g (- \frac{f}{x ^{2}} + 1) (- \frac{g}{x} + 1)

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\frac{12 t ^{2} ( 5 - t )}{625}

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(x + 35) (x - 35)

What is (f\circ g)(f/(-x^2)+1)(g/(-x)+1) ?
The solution to (f\circ g)(f/(-x^2)+1)(g/(-x)+1) is \circ fg(-f/(x^2)+1)(-g/x+1)