What is expand f'(x)5x^3(x^2-9) ?

The solution to expand f'(x)5x^3(x^2-9) is 5x^5f'(x)-45x^3f'(x)

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expand f'(x)5x^3(x^2-9)

expand

f^{'} (x) 5 x^{3} (x^{2} - 9)

5 x^{5} f' (x) - 45 x^{3} f' (x)

Solution steps

f^{'} (x) 5 x^{3} (x^{2} - 9)

= 5 x^{3} f^{^{'}} (x) (x^{2} - 9)

Apply the distributive law:

a (b - c) = ab - a c

a = f^{'} (x) 5 x^{3}, b = x^{2}, c = 9

= f^{^{'}} (x) 5 x^{3} x^{2} - f^{^{'}} (x) 5 x^{3} \cdot 9

= 5 x^{3} x^{2} f^{^{'}} (x) - 5 \cdot 9 x^{3} f^{^{'}} (x)

Simplify

5 x^{3} x^{2} f^{'} (x) - 5 \cdot 9 x^{3} f^{'} (x) : 5 x^{5} f^{'} (x) - 45 x^{3} f^{'} (x)

= 5 x^{5} f^{'} (x) - 45 x^{3} f^{'} (x)

\frac{1}{2} (sin (x) + \frac{1}{5} sin (5 x))

(\frac{1}{0.5 x + 2} + 2) \cdot 0.5

(- b + d) (- b - d)

\frac{1}{2} (8 + lo g_{2} (3))

(4 sin (x) + 3) (sin (x) - 1)

What is expand f'(x)5x^3(x^2-9) ?
The solution to expand f'(x)5x^3(x^2-9) is 5x^5f'(x)-45x^3f'(x)