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Popular >

d/(d{x)}(({z}(x,y))(8e^{9{x}}-8ln({y})))

Solution

\frac{d}{d x} ((z (x, y)) (8 e^{9 x} - 8 ln (y)))

Solution

z (x, y) (72 e^{9 x} - 0)

Solution steps

\frac{d}{d x} ((z (x, y)) (8 e^{9 x} - 8 ln (y)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z (x, y) \frac{d}{d x} (8 e^{9 x} - 8 ln (y))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z (x, y) (\frac{d}{d x} (8 e^{9 x}) - \frac{d}{d x} (8 ln (y)))

\frac{d}{d x} (8 e^{9 x}) = 72 e^{9 x}

\frac{d}{d x} (8 ln (y)) = 0

= z (x, y) (72 e^{9 x} - 0)

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Frequently Asked Questions (FAQ)

What is the d/(d{x)}(({z}(x,y))(8e^{9{x}}-8ln({y}))) ?
The d/(d{x)}(({z}(x,y))(8e^{9{x}}-8ln({y}))) is {z}(x,y)(72e^{9{x}}-0)
What is the first d/(d{x)}(({z}(x,y))(8e^{9{x}}-8ln({y}))) ?
The first d/(d{x)}(({z}(x,y))(8e^{9{x}}-8ln({y}))) is {z}(x,y)(72e^{9{x}}-0)