What is expand (3/2-x/4)((2-x)/3)^2 ?

The solution to expand (3/2-x/4)((2-x)/3)^2 is ((2-x)^2)/6-((2-x)^2x)/(36)

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expand (3/2-x/4)((2-x)/3)^2

expand

(\frac{3}{2} - \frac{x}{4}) (\frac{2 - x}{3})^{2}

\frac{( 2 - x ) ^{2}}{6} - \frac{( 2 - x ) ^{2} x}{36}

Solution steps

(\frac{3}{2} - \frac{x}{4}) (\frac{2 - x}{3})^{2}

= (\frac{2 - x}{3})^{2} (\frac{3}{2} - \frac{x}{4})

Apply the distributive law:

a (b - c) = ab - a c

(\frac{2 - x}{3})^{2} (\frac{3}{2} - \frac{x}{4}) = (\frac{2 - x}{3})^{2} \frac{3}{2} - (\frac{2 - x}{3})^{2} \frac{x}{4}

= (\frac{2 - x}{3})^{2} \frac{3}{2} - (\frac{2 - x}{3})^{2} \frac{x}{4}

Simplify

(\frac{2 - x}{3})^{2} \frac{3}{2} - (\frac{2 - x}{3})^{2} \frac{x}{4} : \frac{( 2 - x ) ^{2}}{6} - \frac{( 2 - x ) ^{2} x}{36}

= \frac{( 2 - x ) ^{2}}{6} - \frac{( 2 - x ) ^{2} x}{36}

\frac{( x - 2 ) ( x + 1 )}{( x - 5 ) ( x - 1 )}

(1 - sin^{2} (x))^{2}

(x - 4)^{4}

0.03 \cdot 1 (1. 2^{1})

(5 x^{2} - 4) (5 w^{2} - \frac{3}{2})

What is expand (3/2-x/4)((2-x)/3)^2 ?
The solution to expand (3/2-x/4)((2-x)/3)^2 is ((2-x)^2)/6-((2-x)^2x)/(36)