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Popular >

expand ((2x+1)3x)/2

Solution

expand

\frac{( 2 x + 1 ) 3 x}{2}

Solution

3 x^{2} + \frac{3 x}{2}

Solution steps

\frac{( 2 x + 1 ) \cdot 3 x}{2}

Expand

(2 x + 1) \cdot 3 x : 6 x^{2} + 3 x

= \frac{6 x ^{2} + 3 x}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x ^{2} + 3 x}{2} = \frac{6 x ^{2}}{2} + \frac{3 x}{2}

= \frac{6 x ^{2}}{2} + \frac{3 x}{2}

Divide the numbers:

\frac{6}{2} = 3

= 3 x^{2} + \frac{3 x}{2}

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Frequently Asked Questions (FAQ)

What is expand ((2x+1)3x)/2 ?
The solution to expand ((2x+1)3x)/2 is 3x^2+(3x)/2