What is expand (1,-2,5,-3)(2,3,1,-4)y(3,8,-3,-5) ?

The solution to expand (1,-2,5,-3)(2,3,1,-4)y(3,8,-3,-5) is

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expand (1,-2,5,-3)(2,3,1,-4)y(3,8,-3,-5)

expand

(1, - 2, 5, - 3) (2, 3, 1, - 4) y (3, 8, - 3, - 5)

1 \cdot y, 2, 3, 1, 3, 8, - 1 \cdot y, 2, 3, 1, 3, - 1 \cdot y, 2, 3, 1, 5 - 1 \cdot y, 4 \cdot 3, 8, 1, 4 \cdot 3, 1, 4 \cdot 5 - 2 y, 5, 2, 3, 1, 2, 5, 4 \cdot 3, 8, 2, 5, 2, 3, 1, 2, 5, 4 \cdot 3, 2, 5, 2, 3, 1, 2, 5, 4 \cdot 5 - 3 \cdot 2 y, 3, 1, 3 \cdot 4 \cdot 3, 8, 3 \cdot 2, 3, 1, 3 \cdot 4 \cdot 3, 3 \cdot 2, 3, 1, 3 \cdot 4 \cdot 5

Solution steps

(1, - 2, 5, - 3) (2, 3, 1, - 4) y (3, 8, - 3, - 5)

= (1, - 2 \cdot 5,, - 3) (2 \cdot 3 \cdot 1,,, - 4) (3 \cdot 8,, - 3, - 5) y

Expand

(1, - 2, 5, - 3) (2, 3, 1, - 4) : 1, 2, 3, 1, - 1, 4 - 2, 5, 2, 3, 1, 2, 5, 4 - 3 \cdot 2, 3, 1, 3 \cdot 4

= y (1, 2, 3, 1, - 1, 4 - 2, 5, 2, 3, 1, 2, 5, 4 - 3 \cdot 2, 3, 1, 3 \cdot 4) (3, 8, - 3, - 5)

Expand

(1, 2, 3, 1, - 1, 4 - 2, 5, 2, 3, 1, 2, 5, 4 - 3 \cdot 2, 3, 1, 3 \cdot 4) (3, 8, - 3, - 5) : 1, 2, 3, 1, 3, 8, - 1, 2, 3, 1, 3, - 1, 2, 3, 1, 5 - 1, 4 \cdot 3, 8, 1, 4 \cdot 3, 1, 4 \cdot 5 - 2, 5, 2, 3, 1, 2, 5, 4 \cdot 3, 8, 2, 5, 2, 3, 1, 2, 5, 4 \cdot 3, 2, 5, 2, 3, 1, 2, 5, 4 \cdot 5 - 3 \cdot 2, 3, 1, 3 \cdot 4 \cdot 3, 8, 3 \cdot 2, 3, 1, 3 \cdot 4 \cdot 3, 3 \cdot 2, 3, 1, 3 \cdot 4 \cdot 5

= y (1, 2, 3, 1, 3, 8, - 1, 2, 3, 1, 3, - 1, 2, 3, 1, 5 - 1, 4 \cdot 3, 8, 1, 4 \cdot 3, 1, 4 \cdot 5 - 2, 5, 2, 3, 1, 2, 5, 4 \cdot 3, 8, 2, 5, 2, 3, 1, 2, 5, 4 \cdot 3, 2, 5, 2, 3, 1, 2, 5, 4 \cdot 5 - 3 \cdot 2, 3, 1, 3 \cdot 4 \cdot 3, 8, 3 \cdot 2, 3, 1, 3 \cdot 4 \cdot 3, 3 \cdot 2, 3, 1, 3 \cdot 4 \cdot 5)

Expand

y (1, 2, 3, 1, 3, 8, - 1, 2, 3, 1, 3, - 1, 2, 3, 1, 5 - 1, 4 \cdot 3, 8, 1, 4 \cdot 3, 1, 4 \cdot 5 - 2, 5, 2, 3, 1, 2, 5, 4 \cdot 3, 8, 2, 5, 2, 3, 1, 2, 5, 4 \cdot 3, 2, 5, 2, 3, 1, 2, 5, 4 \cdot 5 - 3 \cdot 2, 3, 1, 3 \cdot 4 \cdot 3, 8, 3 \cdot 2, 3, 1, 3 \cdot 4 \cdot 3, 3 \cdot 2, 3, 1, 3 \cdot 4 \cdot 5) : 1 \cdot y, 2, 3, 1, 3, 8, - 1 \cdot y, 2, 3, 1, 3, - 1 \cdot y, 2, 3, 1, 5 - 1 \cdot y, 4 \cdot 3, 8, 1, 4 \cdot 3, 1, 4 \cdot 5 - 2 y, 5, 2, 3, 1, 2, 5, 4 \cdot 3, 8, 2, 5, 2, 3, 1, 2, 5, 4 \cdot 3, 2, 5, 2, 3, 1, 2, 5, 4 \cdot 5 - 3 \cdot 2 y, 3, 1, 3 \cdot 4 \cdot 3, 8, 3 \cdot 2, 3, 1, 3 \cdot 4 \cdot 3, 3 \cdot 2, 3, 1, 3 \cdot 4 \cdot 5

= 1 \cdot y, 2, 3, 1, 3, 8, - 1 \cdot y, 2, 3, 1, 3, - 1 \cdot y, 2, 3, 1, 5 - 1 \cdot y, 4 \cdot 3, 8, 1, 4 \cdot 3, 1, 4 \cdot 5 - 2 y, 5, 2, 3, 1, 2, 5, 4 \cdot 3, 8, 2, 5, 2, 3, 1, 2, 5, 4 \cdot 3, 2, 5, 2, 3, 1, 2, 5, 4 \cdot 5 - 3 \cdot 2 y, 3, 1, 3 \cdot 4 \cdot 3, 8, 3 \cdot 2, 3, 1, 3 \cdot 4 \cdot 3, 3 \cdot 2, 3, 1, 3 \cdot 4 \cdot 5

\frac{ln ( - x + 1 ) ( - x + 1 ) - x ln ( x )}{x ln ( x )}

\frac{6 cos ^{3} ( s - 2 ) - 6 s ^{4} + 24 s - 48}{s ^{4} ( s - 2 )}

\frac{2 ( k ^{3} + 3 k ^{2} + 5 k + 2 )}{3}

\frac{sec ( 2 ( x + y ) ) - sec ( 2 x )}{y}

What is expand (1,-2,5,-3)(2,3,1,-4)y(3,8,-3,-5) ?
The solution to expand (1,-2,5,-3)(2,3,1,-4)y(3,8,-3,-5) is