What is expand (x+L*cos(TH))^2 ?

The solution to expand (x+L*cos(TH))^2 is x^2+2xLcos(TH)+L^2cos^2(TH)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x+L*cos(TH))^2

expand

(x + L \cdot cos (T H))^{2}

x^{2} + 2 xL cos (T H) + L^{2} cos^{2} (T H)

Solution steps

(x + L cos (T H))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(x + L cos (T H))^{2} = x^{2} + 2 xL cos (T H) + (L cos (T H))^{2}

= x^{2} + 2 xL cos (T H) + (L cos (T H))^{2}

Simplify

(L cos (T H))^{2} : L^{2} cos^{2} (T H)

= x^{2} + 2 xL cos (T H) + L^{2} cos^{2} (T H)

2 (e^{3 y x} + 3 y e^{3 y x} x) + 2 y x - y^{3}

\frac{x - 2}{( x + 1 ) ( x - 3 )}

(1 + u^{\frac{1}{2}})^{3}

cos^{2} (t) (1 - t) (7 - t^{3})

sin (θ) (- 5, - 6)

What is expand (x+L*cos(TH))^2 ?
The solution to expand (x+L*cos(TH))^2 is x^2+2xLcos(TH)+L^2cos^2(TH)