What is expand sin(θ)(-5,-6) ?

The solution to expand sin(θ)(-5,-6) is -5sin(θ),-6sin(θ)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand sin(θ)(-5,-6)

expand

sin (θ) (- 5, - 6)

- 5 sin (θ), - 6 sin (θ)

Solution steps

sin (θ) (- 5, - 6)

= (- 5, - 6) sin (θ)

Apply the distributive law:

a (b - c) = ab - a c

a = sin (θ), b = - 5,, c = 6

= sin (θ) (- 5,) - sin (θ) \cdot 6

Apply minus-plus rules

+ (- a) = - a

= - 5 sin (θ), - 6 sin (θ)

(4 - \frac{2}{3} x)^{2}

\frac{1}{( s - 6 ) ^{3}}

\frac{3 ( ( x + 1 ) ^{2} - x ^{6} )}{2}

- \frac{( x - 1 ) ( 10 x ^{2} - 30 x - 63 )}{10}

(2 - 4 i)^{8}

What is expand sin(θ)(-5,-6) ?
The solution to expand sin(θ)(-5,-6) is -5sin(θ),-6sin(θ)