What is expand (3x-1)/((x^2-9)(x^2-1)) ?

The solution to expand (3x-1)/((x^2-9)(x^2-1)) is (3x-1)/(x^4-10x^2+9)

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expand (3x-1)/((x^2-9)(x^2-1))

expand

\frac{3 x - 1}{( x ^{2} - 9 ) ( x ^{2} - 1 )}

\frac{3 x - 1}{x ^{4} - 10 x ^{2} + 9}

Solution steps

\frac{3 x - 1}{( x ^{2} - 9 ) ( x ^{2} - 1 )}

Expand

(x^{2} - 9) (x^{2} - 1) : x^{4} - 10 x^{2} + 9

= \frac{3 x - 1}{x ^{4} - 10 x ^{2} + 9}

(3 x^{2} + x + 3 \circ x + 4) (- 1)

- 10 (52 - 8)

(cos (\frac{2 π}{9}) - cos (x))^{2} + (sin (\frac{2 π}{9}) - sin (x))^{2}

(y - \frac{3}{2} x) (y - \frac{1}{2} x) (y - \frac{2}{15} x)

\frac{t ^{4} + 1 ( t - 1 )}{t ( t ^{2} - 2 )}

What is expand (3x-1)/((x^2-9)(x^2-1)) ?
The solution to expand (3x-1)/((x^2-9)(x^2-1)) is (3x-1)/(x^4-10x^2+9)