What is expand (ax^2+bx+c)/((x^2+1)(x-3)) ?

The solution to expand (ax^2+bx+c)/((x^2+1)(x-3)) is (ax^2+bx+c)/(x^3-3x^2+x-3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (ax^2+bx+c)/((x^2+1)(x-3))

expand

\frac{a x ^{2} + b x + c}{( x ^{2} + 1 ) ( x - 3 )}

\frac{a x ^{2} + b x + c}{x ^{3} - 3 x ^{2} + x - 3}

Solution steps

\frac{a x ^{2} + b x + c}{( x ^{2} + 1 ) ( x - 3 )}

Expand

(x^{2} + 1) (x - 3) : x^{3} - 3 x^{2} + x - 3

= \frac{a x ^{2} + b x + c}{x ^{3} - 3 x ^{2} + x - 3}

12 (lo g_{a} (b) + lo g_{b} (c))

2^{2} + 3^{2}

\frac{2 ( k + 1 ) ( k + 2 ) ( 2 k + 2 )}{3}

\frac{K ( s ^{2} + 4 s + 8 )}{s ^{3} + s ^{2}}

\frac{( x - 6 ) ^{6}}{x}

What is expand (ax^2+bx+c)/((x^2+1)(x-3)) ?
The solution to expand (ax^2+bx+c)/((x^2+1)(x-3)) is (ax^2+bx+c)/(x^3-3x^2+x-3)