What is expand ((-1)^nn!)/(6^n(n+2)) ?

The solution to expand ((-1)^nn!)/(6^n(n+2)) is ((-1)^nn!)/(6^nn+3^n*2^{1+n)}

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expand ((-1)^nn!)/(6^n(n+2))

expand

\frac{( - 1 ) ^{n} n !}{6 ^{n} ( n + 2 )}

\frac{( - 1 ) ^{n} n !}{6 ^{n} n + 3 ^{n} \cdot 2 ^{1 + n}}

Solution steps

\frac{( - 1 ) ^{n} n !}{6 ^{n} ( n + 2 )}

Expand

6^{n} (n + 2) : 6^{n} n + 3^{n} \cdot 2^{1 + n}

= \frac{( - 1 ) ^{n} n !}{6 ^{n} n + 3 ^{n} \cdot 2 ^{n + 1}}

\frac{( - a ( n ) ^{3} + a ( n ) \cdot ( 1 + 6 n ) )}{6}

12 (\frac{x - 4}{4} + \frac{x}{3} = \frac{6}{1})

(z + 3)^{2}

\frac{( - x ^{2} - 64 )}{( x ^{2} - 64 ) ^{2}}

What is expand ((-1)^nn!)/(6^n(n+2)) ?
The solution to expand ((-1)^nn!)/(6^n(n+2)) is ((-1)^nn!)/(6^nn+3^n*2^{1+n)}