What is expand (2(x^3-3x^2-3x-1))/(x^3(x+1)^3) ?

The solution to expand (2(x^3-3x^2-3x-1))/(x^3(x+1)^3) is (2x^3-6x^2-6x-2)/(x^6+3x^5+3x^4+x^3)

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expand (2(x^3-3x^2-3x-1))/(x^3(x+1)^3)

expand

\frac{2 ( x ^{3} - 3 x ^{2} - 3 x - 1 )}{x ^{3} ( x + 1 ) ^{3}}

\frac{2 x ^{3} - 6 x ^{2} - 6 x - 2}{x ^{6} + 3 x ^{5} + 3 x ^{4} + x ^{3}}

Solution steps

\frac{2 ( x ^{3} - 3 x ^{2} - 3 x - 1 )}{x ^{3} ( x + 1 ) ^{3}}

(x + 1)^{3} = x^{3} + 3 x^{2} + 3 x + 1

= \frac{2 ( x ^{3} - 3 x ^{2} - 3 x - 1 )}{x ^{3} ( x ^{3} + 3 x ^{2} + 3 x + 1 )}

Expand

x^{3} (x^{3} + 3 x^{2} + 3 x + 1) : x^{6} + 3 x^{5} + 3 x^{4} + x^{3}

= \frac{2 ( x ^{3} - 3 x ^{2} - 3 x - 1 )}{x ^{6} + 3 x ^{5} + 3 x ^{4} + x ^{3}}

Expand

2 (x^{3} - 3 x^{2} - 3 x - 1) : 2 x^{3} - 6 x^{2} - 6 x - 2

= \frac{2 x ^{3} - 6 x ^{2} - 6 x - 2}{x ^{6} + 3 x ^{5} + 3 x ^{4} + x ^{3}}

\frac{1}{( 12965 e - 3 \cdot s + 1 ) ^{3}}

\frac{( 1 - x ^{2} ) ^{2}}{2}

(e^{x} + e^{- x}) (e^{x} + e^{- x})

\frac{ln ( s )}{s ( s + 1 )}

(1 + x + 5)^{2}

What is expand (2(x^3-3x^2-3x-1))/(x^3(x+1)^3) ?
The solution to expand (2(x^3-3x^2-3x-1))/(x^3(x+1)^3) is (2x^3-6x^2-6x-2)/(x^6+3x^5+3x^4+x^3)