What is expand ((-1)^n)/(2^n(3n+1)) ?

The solution to expand ((-1)^n)/(2^n(3n+1)) is ((-1)^n)/(3*2^nn+2^n)

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expand ((-1)^n)/(2^n(3n+1))

expand

\frac{( - 1 ) ^{n}}{2 ^{n} ( 3 n + 1 )}

\frac{( - 1 ) ^{n}}{3 \cdot 2 ^{n} n + 2 ^{n}}

Solution steps

\frac{( - 1 ) ^{n}}{2 ^{n} ( 3 n + 1 )}

Expand

2^{n} (3 n + 1) : 3 \cdot 2^{n} n + 2^{n}

= \frac{( - 1 ) ^{n}}{3 \cdot 2 ^{n} n + 2 ^{n}}

5 (7 - 10)

\frac{10 x}{( x ^{2} + 1 ) ^{2}}

\frac{1}{4} (3 (1, 2, 3, - 2) + 2 (0, - 2, 1, 2) - (2, - 2, 1, 3))

\frac{2 n + 3}{( n - 1 ) n ( n + 1 )}

x \cdot y \cdot (4 - x^{2} - \frac{y ^{2}}{4})

What is expand ((-1)^n)/(2^n(3n+1)) ?
The solution to expand ((-1)^n)/(2^n(3n+1)) is ((-1)^n)/(3*2^nn+2^n)