What are the solutions to the equation t^2-6t-16=0 ?

The solutions to the equation t^2-6t-16=0 are t=8,t=-2

Find the zeros of t^2-6t-16=0

The zeros of t^2-6t-16=0 are t=8,t=-2

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t^{2} - 6 t - 16 = 0

t = 8, t = - 2

Solution steps

t^{2} - 6 t - 16 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 16) = 10

t_{1, 2} = \frac{- ( - 6 ) \pm 10}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 6 ) + 10}{2 \cdot 1}, t_{2} = \frac{- ( - 6 ) - 10}{2 \cdot 1}

t = \frac{- ( - 6 ) + 10}{2 \cdot 1} : 8

t = \frac{- ( - 6 ) - 10}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

t = 8, t = - 2

211 + 4

14 w^{3} + 7 w^{2} - 46 w - 23

7 = \frac{1}{6} s + 11

- 2 q + 3 (7 q + 6) \leq 10 q - 1 - 7

(z + 9) (z - 2) = (z + 6) (z - 20)

What are the solutions to the equation t^2-6t-16=0 ?
The solutions to the equation t^2-6t-16=0 are t=8,t=-2
Find the zeros of t^2-6t-16=0
The zeros of t^2-6t-16=0 are t=8,t=-2