What is (3+2i)+(3-2i) ?

The solution to (3+2i)+(3-2i) is 6

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simplify (3+2i)+(3-2i)

simplify

(3 + 2 i) + (3 - 2 i)

6

Solution steps

(3 + 2 i) + (3 - 2 i)

Group the real part and the imaginary part of the complex number

(a + bi) + (c + d i) = (a + c) + (b + d) i

= (3 + 3) + (2 - 2) i

Simplify

(3 + 3) + (2 - 2) i : 6

= 6

\frac{1}{7} + \frac{2}{3}

\frac{5}{\frac{1}{4}}

x^{2} - 3 x + 6 = 0

(\frac{5}{2})^{- 3}

(8 a b^{2})^{- \frac{1}{2}} (8 a b^{2})^{\frac{1}{2}}