What is ((3+2x)(x-1))/3-1>((x-1)^2)/4-(1+x)/2 ?

The solution to ((3+2x)(x-1))/3-1>((x-1)^2)/4-(1+x)/2 is x 1

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((3+2x)(x-1))/3-1>((x-1)^2)/4-(1+x)/2

\frac{( 3 + 2 x ) ( x - 1 )}{3} - 1 > \frac{( x - 1 ) ^{2}}{4} - \frac{1 + x}{2}

x < - \frac{21}{5} or x > 1

Interval Notation

(- \infty, - \frac{21}{5}) \cup (1, \infty)

Decimal Notation

x < - 4.2 or x > 1

Solution steps

\frac{( 3 + 2 x ) ( x - 1 )}{3} - 1 > \frac{( x - 1 ) ^{2}}{4} - \frac{1 + x}{2}

Rewrite in standard form

5 x^{2} + 16 x - 21 > 0

Factor

5 x^{2} + 16 x - 21 : (x - 1) (5 x + 21)

(x - 1) (5 x + 21) > 0

Identify the intervals

x < - \frac{21}{5} or x > 1

x^{5} - 32

3 y^{2} - 4 y - 7

4 (w + 1) + w = 5 (w - 1) + 9

n^{2} - 8 n + 16 = 25

2 x + 2 \leq - 4

What is ((3+2x)(x-1))/3-1>((x-1)^2)/4-(1+x)/2 ?
The solution to ((3+2x)(x-1))/3-1>((x-1)^2)/4-(1+x)/2 is x<-21/5 \lor x>1