What are the solutions to the equation n^2-8n+16=25 ?

The solutions to the equation n^2-8n+16=25 are n=9,n=-1

Find the zeros of n^2-8n+16=25

The zeros of n^2-8n+16=25 are n=9,n=-1

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n^{2} - 8 n + 16 = 25

n = 9, n = - 1

Solution steps

n^{2} - 8 n + 16 = 25

Move

25

to the left side

n^{2} - 8 n - 9 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 9) = 10

n_{1, 2} = \frac{- ( - 8 ) \pm 10}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 8 ) + 10}{2 \cdot 1}, n_{2} = \frac{- ( - 8 ) - 10}{2 \cdot 1}

n = \frac{- ( - 8 ) + 10}{2 \cdot 1} : 9

n = \frac{- ( - 8 ) - 10}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

n = 9, n = - 1

2 x + 2 \leq - 4

4 x - 1 = 11

x^{2} - 15 x = - 54

5 > 2 - x

2 (3 x + 8) = 70

What are the solutions to the equation n^2-8n+16=25 ?
The solutions to the equation n^2-8n+16=25 are n=9,n=-1
Find the zeros of n^2-8n+16=25
The zeros of n^2-8n+16=25 are n=9,n=-1